select NAME, rank, count, surname_entries.id 'wiki_id' from surnames left join surname_entries on surname_entries.surname = surnames.name and surname_entries.entry_type = 1 where index2 = 'AL' order by rank asc limit 0,100 Surnames > A > AL > %22

Surnames > A > AL > %22

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
AA AB AC AD AE AF AG AH AI AJ AK AL AM AN AO AP AQ AR AS AT AU AV AW AX AY AZ
AL ALA ALB ALC ALD ALE ALF ALG ALH ALI ALJ ALK ALL ALM ALN ALO ALP ALQ ALR ALS ALT ALU ALV ALW ALY ALZ

Full Surname List Starting with %22(Alphabetical)